Los Angeles Rams: Four games that will define the 2019 season

By Jason Reed | Apr 19, 2019

NEW ORLEANS, LOUISIANA - JANUARY 20: Jared Goff #16 of the Los Angeles Rams calls a play against the New Orleans Saints during the first quarter in the NFC Championship game at the Mercedes-Benz Superdome on January 20, 2019 in New Orleans, Louisiana. (Photo by Streeter Lecka/Getty Images) /

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(Photo by Chris Graythen/Getty Images) – Los Angeles Rams /

The 2019 NFL schedules have been released and the Los Angeles Rams have several tough matchups after representing the NFC in the Super Bowl.

The Los Angeles Rams are going to have a very tough, but very entertaining schedule ahead of them in the 2019 season. The Rams have seven games against 2018 playoff teams, which includes two against the Seattle Seahawks, as well as games against other tough teams that are bound to improve, such as the Cleveland Browns.

If the Los Angeles Rams win their third consecutive NFC West crown then it will be well deserved and will cement the team as a potential dynasty, especially if they can eventually get over the hump and win it all.

Until then, we have to focus on the regular season and there are already some games that are circled. Instead of going with the toughest games or the easiest games, we decided to pinpoint the four games that will define the Los Angeles Rams’ season the most.

Whether the Rams win or lose, these games will determine what kind of team they are and give them an identity for the 2019 campaign. Not every game is as meaningful as the other and we are here to explain to you why these four games will be the most telling about the Los Angeles Rams.

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